Marc h 14 is Pi Day. Pi represents the ratio of the circumference of a circle to its diameter. For the following problems, use 3.14 as an approximation for π.

Charlize has a fence around her 15‐foot by 20‐foot garden. If she decides to reconfigure her garden into a circle and she only wants to use the fence she already has to enclose it, what is the area of the largest possible circular garden Charlize could create? Express your answer as a decimal to the nearest hundredth.

First, we need to figure out how much fence she has. Her original garden is 15 by 20, so she must have 15 + 20 + 15 + 20 = 70 feet of fence. The largest circular garden she can create will use all of the fence that surrounded the old garden (thus, the perimeter, or circumference, of the circle should be 70 feet). If the circumference is 70 feet, the diameter is 70/3.14 = 22.29299363 feet. This means the radius is 22.29299363/2 = 11.14649682 feet and the area is (11.14649682)2(3.14) = 390.127388865, which is 390.13 to the nearest hundredth.

The figure below is made up of four congruent circles. Each circle is tangent to two of the three other circles, as shown. If the radius of each of the circles is 6 units, what is the area of the shaded region in the figure below? Express your answer as a decimal to the nearest hundredth.

If we draw radii from the centers of each of the circles to the points where the circles are tangent, as shown, we can see that a square is formed. The sides of this square are 2(r) = 2(6) = 12 units long, and thus, the area is (12)(12) = 144 square units. If we subtract the area of the four quarter-circles that are in the corners of the square, we are left with the area of the shaded region. So, 144 – 4(1/4)[62(3.14)] = 30.96 square units, to the nearest hundredth.

The area of the entire figure shown below is 7/4 of the area of one of the circles in the figure. If the radius of each of the circles is 4 cm, what is the area of overlap? Express your answer as a decimal to the nearest hundredth.

The area of one circle is 42(3.14) = 50.24 square centimeters. Thus, the area of the entire figure must be (7/4)(50.24) = 87.92 square centimeters. If there was no overlap, the two circles would have a combined area of 2(50.24) = 100.48 square centimeters. This means that the area of the overlap must be 100.48 – 87.92 = 12.56 square centimeters, to the nearest hundredth.

♦ Page 1 of the linked PDF contains PROBLEMS & SOLUTIONS.

Page 2 contains ONLY PROBLEMS. ♦

CCSS (Common Core State Standard)